Sr Examen

Expresión a\dv(b&d)(avb)&(c&d)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a|(d∨(b∧c∧d∧(a∨b)))
    $$a | \left(d \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right)\right)$$
    Solución detallada
    $$b \wedge c \wedge d \wedge \left(a \vee b\right) = b \wedge c \wedge d$$
    $$d \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right) = d$$
    $$a | \left(d \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right)\right) = \neg a \vee \neg d$$
    Simplificación [src]
    $$\neg a \vee \neg d$$
    (¬a)∨(¬d)
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNCD [src]
    $$\neg a \vee \neg d$$
    (¬a)∨(¬d)
    FNDP [src]
    $$\neg a \vee \neg d$$
    (¬a)∨(¬d)
    FND [src]
    Ya está reducido a FND
    $$\neg a \vee \neg d$$
    (¬a)∨(¬d)
    FNC [src]
    Ya está reducido a FNC
    $$\neg a \vee \neg d$$
    (¬a)∨(¬d)