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Lógica matemática/ abcvdv¬a¬bc¬dv¬abc¬dv¬a¬bc¬dv¬ab¬c¬dv¬a¬b¬c¬d

Expresión abcvdv¬a¬bc¬dv¬abc¬dv¬a¬bc¬dv¬ab¬c¬dv¬a¬b¬c¬d

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    d∨(a∧b∧c)∨(b∧c∧(¬a)∧(¬d))∨(b∧(¬a)∧(¬c)∧(¬d))∨(c∧(¬a)∧(¬b)∧(¬d))∨((¬a)∧(¬b)∧(¬c)∧(¬d))
    $$d \vee \left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a \wedge \neg d\right) \vee \left(b \wedge \neg a \wedge \neg c \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b \wedge \neg d\right) \vee \left(\neg a \wedge \neg b \wedge \neg c \wedge \neg d\right)$$
    Solución detallada
    $$d \vee \left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a \wedge \neg d\right) \vee \left(b \wedge \neg a \wedge \neg c \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b \wedge \neg d\right) \vee \left(\neg a \wedge \neg b \wedge \neg c \wedge \neg d\right) = d \vee \left(b \wedge c\right) \vee \neg a$$
    Simplificación [src]
    $$d \vee \left(b \wedge c\right) \vee \neg a$$ 
    d∨(¬a)∨(b∧c)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNDP [src]
    $$d \vee \left(b \wedge c\right) \vee \neg a$$ 
    d∨(¬a)∨(b∧c)
    FND [src]
    Ya está reducido a FND
    $$d \vee \left(b \wedge c\right) \vee \neg a$$ 
    d∨(¬a)∨(b∧c)
    FNCD [src]
    $$\left(b \vee d \vee \neg a\right) \wedge \left(c \vee d \vee \neg a\right)$$ 
    (b∨d∨(¬a))∧(c∨d∨(¬a))
    FNC [src]
    $$\left(b \vee d \vee \neg a\right) \wedge \left(c \vee d \vee \neg a\right)$$ 
    (b∨d∨(¬a))∧(c∨d∨(¬a))
    © Sr Examen