Expresión del cuadrado perfecto
Expresemos el cuadrado perfecto del trinomio cuadrático
$$\left(y^{4} + 2 y^{2}\right) + 2$$
Para eso usemos la fórmula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
donde
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
En nuestro caso
$$a = 1$$
$$b = 2$$
$$c = 2$$
Entonces
$$m = 1$$
$$n = 1$$
Pues,
$$\left(y^{2} + 1\right)^{2} + 1$$
/ ___________ ___________\ / ___________ ___________\ / ___________ ___________\ / ___________ ___________\
| / ___ / ___ | | / ___ / ___ | | / ___ / ___ | | / ___ / ___ |
| 4 ___ / 1 \/ 2 4 ___ / 1 \/ 2 | | 4 ___ / 1 \/ 2 4 ___ / 1 \/ 2 | | 4 ___ / 1 \/ 2 4 ___ / 1 \/ 2 | | 4 ___ / 1 \/ 2 4 ___ / 1 \/ 2 |
|x + \/ 2 * / - - ----- + I*\/ 2 * / - + ----- |*|x + \/ 2 * / - - ----- - I*\/ 2 * / - + ----- |*|x + - \/ 2 * / - - ----- + I*\/ 2 * / - + ----- |*|x + - \/ 2 * / - - ----- - I*\/ 2 * / - + ----- |
\ \/ 2 4 \/ 2 4 / \ \/ 2 4 \/ 2 4 / \ \/ 2 4 \/ 2 4 / \ \/ 2 4 \/ 2 4 /
$$\left(x + \left(\sqrt[4]{2} \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} - \sqrt[4]{2} i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\right)\right) \left(x + \left(\sqrt[4]{2} \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} + \sqrt[4]{2} i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\right)\right) \left(x + \left(- \sqrt[4]{2} \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} + \sqrt[4]{2} i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\right)\right) \left(x + \left(- \sqrt[4]{2} \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}} - \sqrt[4]{2} i \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}\right)\right)$$
(((x + 2^(1/4)*sqrt(1/2 - sqrt(2)/4) + i*2^(1/4)*sqrt(1/2 + sqrt(2)/4))*(x + 2^(1/4)*sqrt(1/2 - sqrt(2)/4) - i*2^(1/4)*sqrt(1/2 + sqrt(2)/4)))*(x - 2^(1/4)*sqrt(1/2 - sqrt(2)/4) + i*2^(1/4)*sqrt(1/2 + sqrt(2)/4)))*(x - 2^(1/4)*sqrt(1/2 - sqrt(2)/4) - i*2^(1/4)*sqrt(1/2 + sqrt(2)/4))