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Suma de la serie x^n/((16^n)(n+2))



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Solución

Ha introducido [src]
  oo             
____             
\   `            
 \          n    
  \        x     
   )  -----------
  /     n        
 /    16 *(n + 2)
/___,            
n = 1            
n=1xn16n(n+2)\sum_{n=1}^{\infty} \frac{x^{n}}{16^{n} \left(n + 2\right)}
Sum(x^n/((16^n*(n + 2))), (n, 1, oo))
Respuesta [src]
/  /                       /    x \\                           
|  |              12288*log|1 - --||                           
|  |-768 - 24*x            \    16/|                           
|x*|----------- - -----------------|                           
|  |      2                3       |                           
|  \     x                x        /                           
|-----------------------------------  for And(x >= -16, x < 16)
|                 48                                           
|                                                              
<             oo                                               
|           ____                                               
|           \   `                                              
|            \      -n  n                                      
|             \   16  *x                                       
|             /   -------                     otherwise        
|            /     2 + n                                       
|           /___,                                              
|           n = 1                                              
\                                                              
{x(24x768x212288log(1x16)x3)48forx16x<16n=116nxnn+2otherwise\begin{cases} \frac{x \left(\frac{- 24 x - 768}{x^{2}} - \frac{12288 \log{\left(1 - \frac{x}{16} \right)}}{x^{3}}\right)}{48} & \text{for}\: x \geq -16 \wedge x < 16 \\\sum_{n=1}^{\infty} \frac{16^{- n} x^{n}}{n + 2} & \text{otherwise} \end{cases}
Piecewise((x*((-768 - 24*x)/x^2 - 12288*log(1 - x/16)/x^3)/48, (x >= -16)∧(x < 16)), (Sum(16^(-n)*x^n/(2 + n), (n, 1, oo)), True))

    Ejemplos de hallazgo de la suma de la serie