Sr Examen

Otras calculadoras

Ecuación diferencial dx*(x^2*y^4+1)*y+2*dy*x=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
 2  5          d                  
x *y (x) + 2*x*--(y(x)) + y(x) = 0
               dx                 
$$x^{2} y^{5}{\left(x \right)} + 2 x \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} = 0$$
x^2*y^5 + 2*x*y' + y = 0
Respuesta [src]
               ____________________
              /         1          
y(x) = -I*   /  ------------------ 
          4 /    2                 
          \/    x *(C1 + 2*log(x)) 
$$y{\left(x \right)} = - i \sqrt[4]{\frac{1}{x^{2} \left(C_{1} + 2 \log{\left(x \right)}\right)}}$$
              ____________________
             /         1          
y(x) = I*   /  ------------------ 
         4 /    2                 
         \/    x *(C1 + 2*log(x)) 
$$y{\left(x \right)} = i \sqrt[4]{\frac{1}{x^{2} \left(C_{1} + 2 \log{\left(x \right)}\right)}}$$
             ____________________
            /         1          
y(x) = -   /  ------------------ 
        4 /    2                 
        \/    x *(C1 + 2*log(x)) 
$$y{\left(x \right)} = - \sqrt[4]{\frac{1}{x^{2} \left(C_{1} + 2 \log{\left(x \right)}\right)}}$$
            ____________________
           /         1          
y(x) =    /  ------------------ 
       4 /    2                 
       \/    x *(C1 + 2*log(x)) 
$$y{\left(x \right)} = \sqrt[4]{\frac{1}{x^{2} \left(C_{1} + 2 \log{\left(x \right)}\right)}}$$
Clasificación
separable reduced
lie group
separable reduced Integral