Sr Examen

Ecuación diferencial x(y^6+1)dx+y^2(x^4+1)dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
       6       2    d           4  2    d           
x + x*y (x) + y (x)*--(y(x)) + x *y (x)*--(y(x)) = 0
                    dx                  dx          
$$x^{4} y^{2}{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + x y^{6}{\left(x \right)} + x + y^{2}{\left(x \right)} \frac{d}{d x} y{\left(x \right)} = 0$$
x^4*y^2*y' + x*y^6 + x + y^2*y' = 0
Respuesta [src]
            ______________________               
           /    /           / 2\\                
          /     |     3*atan\x /|  /         ___\
       3 /   tan|C1 - ----------| *\-1 + I*\/ 3 /
       \/       \         2     /                
y(x) = ------------------------------------------
                           2                     
$$y{\left(x \right)} = \frac{\left(-1 + \sqrt{3} i\right) \sqrt[3]{\tan{\left(C_{1} - \frac{3 \operatorname{atan}{\left(x^{2} \right)}}{2} \right)}}}{2}$$
            ______________________               
           /    /           / 2\\                
          /     |     3*atan\x /|  /         ___\
       3 /   tan|C1 - ----------| *\-1 - I*\/ 3 /
       \/       \         2     /                
y(x) = ------------------------------------------
                           2                     
$$y{\left(x \right)} = \frac{\left(-1 - \sqrt{3} i\right) \sqrt[3]{\tan{\left(C_{1} - \frac{3 \operatorname{atan}{\left(x^{2} \right)}}{2} \right)}}}{2}$$
            ______________________
           /    /           / 2\\ 
          /     |     3*atan\x /| 
y(x) = 3 /   tan|C1 - ----------| 
       \/       \         2     / 
$$y{\left(x \right)} = \sqrt[3]{\tan{\left(C_{1} - \frac{3 \operatorname{atan}{\left(x^{2} \right)}}{2} \right)}}$$
Clasificación
separable
1st power series
lie group
separable Integral