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Ecuación diferencial y'''-4y''+3y'=x^2+xe^(2x)

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
      2                        3                    
     d            d           d           2      2*x
- 4*---(y(x)) + 3*--(y(x)) + ---(y(x)) = x  + x*e   
      2           dx           3                    
    dx                       dx                     
$$3 \frac{d}{d x} y{\left(x \right)} - 4 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = x^{2} + x e^{2 x}$$
3*y' - 4*y'' + y''' = x^2 + x*exp(2*x)
Respuesta [src]
             3      2                                       2*x
            x    4*x    26*x       x       3*x   (1 - 2*x)*e   
y(x) = C1 + -- + ---- + ---- + C2*e  + C3*e    + --------------
            9     9      27                            4       
$$y{\left(x \right)} = C_{1} + C_{2} e^{x} + C_{3} e^{3 x} + \frac{x^{3}}{9} + \frac{4 x^{2}}{9} + \frac{26 x}{27} + \frac{\left(1 - 2 x\right) e^{2 x}}{4}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral