Sr Examen

Ecuación diferencial y+y'ln^2y=(x+2lny)y'

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   2       d                                   d       
log (y(x))*--(y(x)) + y(x) = (x + 2*log(y(x)))*--(y(x))
           dx                                  dx      
$$y{\left(x \right)} + \log{\left(y{\left(x \right)} \right)}^{2} \frac{d}{d x} y{\left(x \right)} = \left(x + 2 \log{\left(y{\left(x \right)} \right)}\right) \frac{d}{d x} y{\left(x \right)}$$
y + log(y)^2*y' = (x + 2*log(y))*y'
Gráfico para el problema de Cauchy
Clasificación
factorable
1st exact
1st power series
lie group
1st exact Integral
Respuesta numérica [src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, 0.5981860857590011)
(-5.555555555555555, 0.4584826131695332)
(-3.333333333333333, 0.3362889680189648)
(-1.1111111111111107, 0.23690935537437302)
(1.1111111111111107, 0.16266931487755387)
(3.333333333333334, 0.11112467293600847)
(5.555555555555557, 0.0767894103322837)
(7.777777777777779, 0.054127606403377694)
(10.0, 0.039002715955154796)
(10.0, 0.039002715955154796)