absolute(x^2+3absolutex-4)=a la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
False
// __________ \ // __________ \
||3 \/ 25 - 4*a | ||3 \/ 25 - 4*a |
||- - ------------ for And(a > 0, a < 4)| ||- - ------------ for And(a > 0, a < 4)|
x2 = I*im|<2 2 | + re|<2 2 |
|| | || |
|| nan otherwise | || nan otherwise |
\\ / \\ /
x2=re({23−225−4aNaNfora>0∧a<4otherwise)+iim({23−225−4aNaNfora>0∧a<4otherwise)
// __________ \ // __________ \
||3 \/ 25 + 4*a | ||3 \/ 25 + 4*a |
||- - ------------ for a >= 0| ||- - ------------ for a >= 0|
x3 = I*im|<2 2 | + re|<2 2 |
|| | || |
|| nan otherwise | || nan otherwise |
\\ / \\ /
x3=re({23−24a+25NaNfora≥0otherwise)+iim({23−24a+25NaNfora≥0otherwise)
// __________ \ // __________ \
|| 3 \/ 25 - 4*a | || 3 \/ 25 - 4*a |
||- - + ------------ for And(a <= 4, a > 0)| ||- - + ------------ for And(a <= 4, a > 0)|
x4 = I*im|< 2 2 | + re|< 2 2 |
|| | || |
|| nan otherwise | || nan otherwise |
\\ / \\ /
x4=re({225−4a−23NaNfora≤4∧a>0otherwise)+iim({225−4a−23NaNfora≤4∧a>0otherwise)
// __________ __________ \ // __________ __________ \
|| 3 \/ 25 + 4*a 3 \/ 25 + 4*a | || 3 \/ 25 + 4*a 3 \/ 25 + 4*a |
||- - - ------------ for - + ------------ <= -1| ||- - - ------------ for - + ------------ <= -1|
x5 = I*im|< 2 2 2 2 | + re|< 2 2 2 2 |
|| | || |
|| nan otherwise | || nan otherwise |
\\ / \\ /
x5=re({−24a+25−23NaNfor24a+25+23≤−1otherwise)+iim({−24a+25−23NaNfor24a+25+23≤−1otherwise)
// __________ __________ \ // __________ __________ \
|| 3 \/ 25 + 4*a 3 \/ 25 + 4*a | || 3 \/ 25 + 4*a 3 \/ 25 + 4*a |
||- - + ------------ for - - + ------------ >= 1| ||- - + ------------ for - - + ------------ >= 1|
x6 = I*im|< 2 2 2 2 | + re|< 2 2 2 2 |
|| | || |
|| nan otherwise | || nan otherwise |
\\ / \\ /
x6=re({24a+25−23NaNfor24a+25−23≥1otherwise)+iim({24a+25−23NaNfor24a+25−23≥1otherwise)
x6 = re(Piecewise((sqrt(4*a + 25/2 - 3/2, sqrt(4*a + 25)/2 - 3/2 >= 1), (nan, True))) + i*im(Piecewise((sqrt(4*a + 25)/2 - 3/2, sqrt(4*a + 25)/2 - 3/2 >= 1), (nan, True))))