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(log(4,(64x)))/(log(4,(x-3)))+(log(4,(x-3)))/(log(4,(64x)))≥(log(4,(x^4+16)))/(log(4,(x-9)))^2 desigualdades

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Solución

Ha introducido [src]
                                    /    4     \
 log(4, 64*x)   log(4, x - 3)    log\4, x  + 16/
------------- + ------------- >= ---------------
log(4, x - 3)    log(4, 64*x)        2          
                                  log (4, x - 9)
$$\frac{\log{\left(4 \right)}}{\log{\left(4 \right)}} + \frac{\log{\left(4 \right)}}{\log{\left(4 \right)}} \geq \frac{\log{\left(4 \right)}}{\log{\left(4 \right)}^{2}}$$
log(4, 64*x)/log(4, x - 3) + log(4, x - 3)/log(4, 64*x) >= log(4, x^4 + 16)/log(4, x - 9)^2