/2 - x\ / 2\ log|-----| - log(x - 2) > -log\(x - 9) / \x - 9/
log((2 - x)/(x - 9)) - log(x - 2) > -log((x - 9)^2)
And(2 < x, x < 8)
(2 < x)∧(x < 8)
(2, 8)
x in Interval.open(2, 8)