2 ___ \/ x + 2*x - 8 > x - 1
(sqrt(x))^2 + 2*x - 8 > x - 1
And(7/2 < x, x < oo)
(7/2 < x)∧(x < oo)
(7/2, oo)
x in Interval.open(7/2, oo)