Sr Examen

Lang:

Resolver desigualdades/ log(x+1)/log(x)+log(x+2)/log(x+1)+log(x)/log(x+2)>=log(x+2)/log(x)+log(x+1)/log(x+2)+log(x)/log(x+1)

log(x+1)/log(x)+log(x+2)/log(x+1)+log(x)/log(x+2)>=log(x+2)/log(x)+log(x+1)/log(x+2)+log(x)/log(x+1) desigualdades

Solución

Ha introducido [src]

log(x + 1)   log(x + 2)     log(x)      log(x + 2)   log(x + 1)     log(x)  
---------- + ---------- + ---------- >= ---------- + ---------- + ----------
  log(x)     log(x + 1)   log(x + 2)      log(x)     log(x + 2)   log(x + 1)

\left(\frac{\log{\left(x + 2 \right)}}{\log{\left(x + 1 \right)}} + \frac{\log{\left(x + 1 \right)}}{\log{\left(x \right)}}\right) + \frac{\log{\left(x \right)}}{\log{\left(x + 2 \right)}} \geq \left(\frac{\log{\left(x + 1 \right)}}{\log{\left(x + 2 \right)}} + \frac{\log{\left(x + 2 \right)}}{\log{\left(x \right)}}\right) + \frac{\log{\left(x \right)}}{\log{\left(x + 1 \right)}}

log(x + 2)/log(x + 1) + log(x + 1)/log(x) + log(x)/log(x + 2) >= log(x + 1)/log(x + 2) + log(x + 2)/log(x) + log(x)/log(x + 1)

Solución de la desigualdad en el gráfico