Sr Examen
Integral de 1/((x^(2*n))+1) dx
Solución
Ha introducido
[src]
1 / | | 1 | -------- dx | 2*n | x + 1 | / 0
$$\int\limits_{0}^{1} \frac{1}{x^{2 n} + 1}\, dx$$
Integral(1/(x^(2*n) + 1), (x, 0, 1))
Respuesta (Indefinida)
[src]
/ / 1 \ / 2*n pi*I 1 \ | x*Gamma|---|*lerchphi|x *e , 1, ---| | 1 \2*n/ \ 2*n/ | -------- dx = C + ----------------------------------------- | 2*n 2 / 1 \ | x + 1 4*n *Gamma|1 + ---| | \ 2*n/ /
$$\int \frac{1}{x^{2 n} + 1}\, dx = C + \frac{x \Phi\left(x^{2 n} e^{i \pi}, 1, \frac{1}{2 n}\right) \Gamma\left(\frac{1}{2 n}\right)}{4 n^{2} \Gamma\left(1 + \frac{1}{2 n}\right)}$$
Respuesta
[src]
/ 1 \ / pi*I 1 \
Gamma|---|*lerchphi|e , 1, ---|
\2*n/ \ 2*n/
----------------------------------
2 / 1 \
4*n *Gamma|1 + ---|
\ 2*n/
$$\frac{\Phi\left(e^{i \pi}, 1, \frac{1}{2 n}\right) \Gamma\left(\frac{1}{2 n}\right)}{4 n^{2} \Gamma\left(1 + \frac{1}{2 n}\right)}$$
=
=
/ 1 \ / pi*I 1 \
Gamma|---|*lerchphi|e , 1, ---|
\2*n/ \ 2*n/
----------------------------------
2 / 1 \
4*n *Gamma|1 + ---|
\ 2*n/
$$\frac{\Phi\left(e^{i \pi}, 1, \frac{1}{2 n}\right) \Gamma\left(\frac{1}{2 n}\right)}{4 n^{2} \Gamma\left(1 + \frac{1}{2 n}\right)}$$
gamma(1/(2*n))*lerchphi(exp_polar(pi*i), 1, 1/(2*n))/(4*n^2*gamma(1 + 1/(2*n)))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.