Integral de (m*x-1)/(x^2-4*x+13) dx
Solución
Respuesta (Indefinida)
[src]
/ / 2 x\ / / 2 x\\
| atan|- - + -| | / 2 \ 2*atan|- - + -||
| m*x - 1 \ 3 3/ |log\13 + x - 4*x/ \ 3 3/|
| ------------- dx = C - ------------- + m*|------------------ + ---------------|
| 2 3 \ 2 3 /
| x - 4*x + 13
|
/
∫(x2−4x)+13mx−1dx=C+m(2log(x2−4x+13)+32atan(3x−32))−3atan(3x−32)
/m I*(-1 + 2*m)\ / 2 - 4*m - 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ / 2 - 4*m + 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ /2 - 4*m - 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ /2 - 4*m + 3*I*(-1 + 2*m)\
|- - ------------|*log|1 + ------------------------| + |- + ------------|*log|1 + ------------------------| - |- - ------------|*log|------------------------| - |- + ------------|*log|------------------------|
\2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m /
−(2m−6i(2m−1))log(2m−1−4m−3i(2m−1)+2)+(2m−6i(2m−1))log(1+2m−1−4m−3i(2m−1)+2)−(2m+6i(2m−1))log(2m−1−4m+3i(2m−1)+2)+(2m+6i(2m−1))log(1+2m−1−4m+3i(2m−1)+2)
=
/m I*(-1 + 2*m)\ / 2 - 4*m - 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ / 2 - 4*m + 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ /2 - 4*m - 3*I*(-1 + 2*m)\ /m I*(-1 + 2*m)\ /2 - 4*m + 3*I*(-1 + 2*m)\
|- - ------------|*log|1 + ------------------------| + |- + ------------|*log|1 + ------------------------| - |- - ------------|*log|------------------------| - |- + ------------|*log|------------------------|
\2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m / \2 6 / \ -1 + 2*m /
−(2m−6i(2m−1))log(2m−1−4m−3i(2m−1)+2)+(2m−6i(2m−1))log(1+2m−1−4m−3i(2m−1)+2)−(2m+6i(2m−1))log(2m−1−4m+3i(2m−1)+2)+(2m+6i(2m−1))log(1+2m−1−4m+3i(2m−1)+2)
(m/2 - i*(-1 + 2*m)/6)*log(1 + (2 - 4*m - 3*i*(-1 + 2*m))/(-1 + 2*m)) + (m/2 + i*(-1 + 2*m)/6)*log(1 + (2 - 4*m + 3*i*(-1 + 2*m))/(-1 + 2*m)) - (m/2 - i*(-1 + 2*m)/6)*log((2 - 4*m - 3*i*(-1 + 2*m))/(-1 + 2*m)) - (m/2 + i*(-1 + 2*m)/6)*log((2 - 4*m + 3*i*(-1 + 2*m))/(-1 + 2*m))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.