Sr Examen
Integral de (8+tanx)^1/2/(1-sin²x) dx
Solución
Ha introducido
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1 / | | ____________ | \/ 8 + tan(x) | -------------- dx | 2 | 1 - sin (x) | / 0
$$\int\limits_{0}^{1} \frac{\sqrt{\tan{\left(x \right)} + 8}}{1 - \sin^{2}{\left(x \right)}}\, dx$$
Integral(sqrt(8 + tan(x))/(1 - sin(x)^2), (x, 0, 1))
Respuesta (Indefinida)
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/ / | | | ____________ | ____________ | \/ 8 + tan(x) | \/ 8 + tan(x) | -------------- dx = C - | -------------------------- dx | 2 | (1 + sin(x))*(-1 + sin(x)) | 1 - sin (x) | | / /
$$\int \frac{\sqrt{\tan{\left(x \right)} + 8}}{1 - \sin^{2}{\left(x \right)}}\, dx = C - \int \frac{\sqrt{\tan{\left(x \right)} + 8}}{\left(\sin{\left(x \right)} - 1\right) \left(\sin{\left(x \right)} + 1\right)}\, dx$$
Respuesta
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1 / | | ____________ | \/ 8 + tan(x) - | -------------- dx | 2 | -1 + sin (x) | / 0
$$- \int\limits_{0}^{1} \frac{\sqrt{\tan{\left(x \right)} + 8}}{\sin^{2}{\left(x \right)} - 1}\, dx$$
=
=
1 / | | ____________ | \/ 8 + tan(x) - | -------------- dx | 2 | -1 + sin (x) | / 0
$$- \int\limits_{0}^{1} \frac{\sqrt{\tan{\left(x \right)} + 8}}{\sin^{2}{\left(x \right)} - 1}\, dx$$
-Integral(sqrt(8 + tan(x))/(-1 + sin(x)^2), (x, 0, 1))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.