Tomamos como el límite
$$\lim_{x \to -1^+}\left(\frac{- 3 x + \left(x^{2} + 2\right)}{3 x^{2} + \left(14 - x\right)}\right)$$
cambiamos
$$\lim_{x \to -1^+}\left(\frac{- 3 x + \left(x^{2} + 2\right)}{3 x^{2} + \left(14 - x\right)}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{\left(x - 2\right) \left(x - 1\right)}{3 x^{2} - x + 14}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{\left(x - 2\right) \left(x - 1\right)}{3 x^{2} - x + 14}\right) = $$
$$\frac{\left(-2 - 1\right) \left(-1 - 1\right)}{- -1 + 3 \left(-1\right)^{2} + 14} = $$
= 1/3
Entonces la respuesta definitiva es:
$$\lim_{x \to -1^+}\left(\frac{- 3 x + \left(x^{2} + 2\right)}{3 x^{2} + \left(14 - x\right)}\right) = \frac{1}{3}$$