Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{- 9 x + \left(x^{2} + 14\right)}{6 x + \left(x^{2} - 7\right)}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{- 9 x + \left(x^{2} + 14\right)}{6 x + \left(x^{2} - 7\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 7\right) \left(x - 2\right)}{\left(x - 1\right) \left(x + 7\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 7\right) \left(x - 2\right)}{\left(x - 1\right) \left(x + 7\right)}\right) = $$
$$\frac{\left(-7 + 2\right) \left(-2 + 2\right)}{\left(-1 + 2\right) \left(2 + 7\right)} = $$
= 0
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{- 9 x + \left(x^{2} + 14\right)}{6 x + \left(x^{2} - 7\right)}\right) = 0$$