Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{2 x \left(x + 1\right)}{2 x^{2} + \left(x^{3} + x\right)}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{2 x \left(x + 1\right)}{2 x^{2} + \left(x^{3} + x\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{2 x \left(x + 1\right)}{x \left(x + 1\right)^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{2}{x + 1}\right) = $$
$$\frac{2}{1} = $$
= 2
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{2 x \left(x + 1\right)}{2 x^{2} + \left(x^{3} + x\right)}\right) = 2$$