Tomamos como el límite
$$\lim_{x \to 3^+}\left(\frac{x^{2} + \left(x + 2\right)}{2 x + \left(x^{2} + 8\right)}\right)$$
cambiamos
$$\lim_{x \to 3^+}\left(\frac{x^{2} + \left(x + 2\right)}{2 x + \left(x^{2} + 8\right)}\right)$$
=
$$\lim_{x \to 3^+}\left(\frac{x^{2} + x + 2}{x^{2} + 2 x + 8}\right)$$
=
$$\lim_{x \to 3^+}\left(\frac{x^{2} + x + 2}{x^{2} + 2 x + 8}\right) = $$
$$\frac{2 + 3 + 3^{2}}{2 \cdot 3 + 8 + 3^{2}} = $$
= 14/23
Entonces la respuesta definitiva es:
$$\lim_{x \to 3^+}\left(\frac{x^{2} + \left(x + 2\right)}{2 x + \left(x^{2} + 8\right)}\right) = \frac{14}{23}$$