Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{x^{2} + \left(x - 2\right)}{4 x + \left(3 x^{2} - 7\right)}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{x^{2} + \left(x - 2\right)}{4 x + \left(3 x^{2} - 7\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x - 1\right) \left(x + 2\right)}{\left(x - 1\right) \left(3 x + 7\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{x + 2}{3 x + 7}\right) = $$
$$\frac{2}{0 \cdot 3 + 7} = $$
= 2/7
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{x^{2} + \left(x - 2\right)}{4 x + \left(3 x^{2} - 7\right)}\right) = \frac{2}{7}$$