Tomamos como el límite
$$\lim_{x \to -1^+}\left(\frac{x^{3} + \left(x^{2} - 11\right)}{8 x^{2} + 5}\right)$$
cambiamos
$$\lim_{x \to -1^+}\left(\frac{x^{3} + \left(x^{2} - 11\right)}{8 x^{2} + 5}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{x^{3} + x^{2} - 11}{8 x^{2} + 5}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{x^{3} + x^{2} - 11}{8 x^{2} + 5}\right) = $$
$$\frac{-11 + \left(-1\right)^{3} + \left(-1\right)^{2}}{5 + 8 \left(-1\right)^{2}} = $$
= -11/13
Entonces la respuesta definitiva es:
$$\lim_{x \to -1^+}\left(\frac{x^{3} + \left(x^{2} - 11\right)}{8 x^{2} + 5}\right) = - \frac{11}{13}$$