Tomamos como el límite
$$\lim_{x \to i_{2}^+}\left(\frac{e \left(\frac{x}{2} + \frac{1}{2}\right)}{x - 2 i}\right)$$
cambiamos
$$\lim_{x \to i_{2}^+}\left(\frac{e \left(\frac{x}{2} + \frac{1}{2}\right)}{x - 2 i}\right)$$
=
$$\lim_{x \to i_{2}^+}\left(\frac{\frac{1}{2} e \left(x + 1\right)}{x - 2 i}\right)$$
=
$$\lim_{x \to i_{2}^+}\left(\frac{e \left(x + 1\right)}{2 \left(x - 2 i\right)}\right) = $$
$$\frac{e \left(i_{2} + 1\right)}{2 \left(i_{2} - 2 i\right)} = $$
= (E + E*i2)/(-4*i + 2*i2)
Entonces la respuesta definitiva es:
$$\lim_{x \to i_{2}^+}\left(\frac{e \left(\frac{x}{2} + \frac{1}{2}\right)}{x - 2 i}\right) = \frac{e i_{2} + e}{2 i_{2} - 4 i}$$