Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{2 x^{2} + \left(x^{3} + x\right)}{x^{4} - 1}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{2 x^{2} + \left(x^{3} + x\right)}{x^{4} - 1}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x \left(x + 1\right)^{2}}{\left(x - 1\right) \left(x + 1\right) \left(x^{2} + 1\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x \left(x + 1\right)}{\left(x - 1\right) \left(x^{2} + 1\right)}\right) = $$
False
= oo
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{2 x^{2} + \left(x^{3} + x\right)}{x^{4} - 1}\right) = \infty$$