Tomamos como el límite
$$\lim_{x \to -2^+}\left(\frac{- 5 x + \left(x^{2} + 6\right)}{3 x + \left(14 - x^{2}\right)}\right)$$
cambiamos
$$\lim_{x \to -2^+}\left(\frac{- 5 x + \left(x^{2} + 6\right)}{3 x + \left(14 - x^{2}\right)}\right)$$
=
$$\lim_{x \to -2^+}\left(\frac{\left(x - 3\right) \left(x - 2\right)}{- x^{2} + 3 x + 14}\right)$$
=
$$\lim_{x \to -2^+}\left(\frac{\left(x - 3\right) \left(x - 2\right)}{- x^{2} + 3 x + 14}\right) = $$
$$\frac{\left(-3 - 2\right) \left(-2 - 2\right)}{\left(-2\right) 3 - \left(-2\right)^{2} + 14} = $$
= 5
Entonces la respuesta definitiva es:
$$\lim_{x \to -2^+}\left(\frac{- 5 x + \left(x^{2} + 6\right)}{3 x + \left(14 - x^{2}\right)}\right) = 5$$