Tenemos la indeterminación de tipo
0/0,
tal que el límite para el numerador es
$$\lim_{x \to 0^+}\left(\frac{x^{2}}{3}\right) = 0$$
y el límite para el denominador es
$$\lim_{x \to 0^+} \frac{1}{\log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}} = 0$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to 0^+}\left(\frac{x^{2} \log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}}{3}\right)$$
=
Introducimos una pequeña modificación de la función bajo el signo del límite
$$\lim_{x \to 0^+}\left(\frac{x^{2} \log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}}{3}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \frac{x^{2}}{3}}{\frac{d}{d x} \frac{1}{\log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}}}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{x^{2} \log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}^{2} \sin{\left(x \right)}}{3 \left(\frac{x \cos{\left(x \right)}}{2} + \frac{\sin{\left(x \right)}}{2}\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(- \frac{x^{2} \log{\left(\frac{x \sin{\left(x \right)}}{2} \right)}^{2} \sin{\left(x \right)}}{3}\right)}{\frac{d}{d x} \left(\frac{x \cos{\left(x \right)}}{2} + \frac{\sin{\left(x \right)}}{2}\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{- \frac{x^{2} \log{\left(x \sin{\left(x \right)} \right)}^{2} \cos{\left(x \right)}}{3} - \frac{2 x^{2} \log{\left(x \sin{\left(x \right)} \right)} \cos{\left(x \right)}}{3} + \frac{2 x^{2} \log{\left(2 \right)} \log{\left(x \sin{\left(x \right)} \right)} \cos{\left(x \right)}}{3} - \frac{x^{2} \log{\left(2 \right)}^{2} \cos{\left(x \right)}}{3} + \frac{2 x^{2} \log{\left(2 \right)} \cos{\left(x \right)}}{3} - \frac{2 x \log{\left(x \sin{\left(x \right)} \right)}^{2} \sin{\left(x \right)}}{3} - \frac{2 x \log{\left(x \sin{\left(x \right)} \right)} \sin{\left(x \right)}}{3} + \frac{4 x \log{\left(2 \right)} \log{\left(x \sin{\left(x \right)} \right)} \sin{\left(x \right)}}{3} - \frac{2 x \log{\left(2 \right)}^{2} \sin{\left(x \right)}}{3} + \frac{2 x \log{\left(2 \right)} \sin{\left(x \right)}}{3}}{- \frac{x \sin{\left(x \right)}}{2} + \cos{\left(x \right)}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{- \frac{x^{2} \log{\left(x \sin{\left(x \right)} \right)}^{2} \cos{\left(x \right)}}{3} - \frac{2 x^{2} \log{\left(x \sin{\left(x \right)} \right)} \cos{\left(x \right)}}{3} + \frac{2 x^{2} \log{\left(2 \right)} \log{\left(x \sin{\left(x \right)} \right)} \cos{\left(x \right)}}{3} - \frac{x^{2} \log{\left(2 \right)}^{2} \cos{\left(x \right)}}{3} + \frac{2 x^{2} \log{\left(2 \right)} \cos{\left(x \right)}}{3} - \frac{2 x \log{\left(x \sin{\left(x \right)} \right)}^{2} \sin{\left(x \right)}}{3} - \frac{2 x \log{\left(x \sin{\left(x \right)} \right)} \sin{\left(x \right)}}{3} + \frac{4 x \log{\left(2 \right)} \log{\left(x \sin{\left(x \right)} \right)} \sin{\left(x \right)}}{3} - \frac{2 x \log{\left(2 \right)}^{2} \sin{\left(x \right)}}{3} + \frac{2 x \log{\left(2 \right)} \sin{\left(x \right)}}{3}}{- \frac{x \sin{\left(x \right)}}{2} + \cos{\left(x \right)}}\right)$$
=
$$0$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 2 vez (veces)