Sr Examen
Factorizar el polinomio z^3-3*z^2+7*z-5
Solución
Ha introducido
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3 2 z - 3*z + 7*z - 5
$$\left(7 z + \left(z^{3} - 3 z^{2}\right)\right) - 5$$
z^3 - 3*z^2 + 7*z - 5
Factorización
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(x - 1)*(x + -1 + 2*I)*(x + -1 - 2*I)
$$\left(x - 1\right) \left(x + \left(-1 + 2 i\right)\right) \left(x + \left(-1 - 2 i\right)\right)$$
((x - 1)*(x - 1 + 2*i))*(x - 1 - 2*i)
Simplificación general
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3 2 -5 + z - 3*z + 7*z
$$z^{3} - 3 z^{2} + 7 z - 5$$
-5 + z^3 - 3*z^2 + 7*z
Combinatoria
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/ 2 \ (-1 + z)*\5 + z - 2*z/
$$\left(z - 1\right) \left(z^{2} - 2 z + 5\right)$$
(-1 + z)*(5 + z^2 - 2*z)
Compilar la expresión
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3 2 -5 + z - 3*z + 7*z
$$z^{3} - 3 z^{2} + 7 z - 5$$
-5 + z^3 - 3*z^2 + 7*z
Parte trigonométrica
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3 2 -5 + z - 3*z + 7*z
$$z^{3} - 3 z^{2} + 7 z - 5$$
-5 + z^3 - 3*z^2 + 7*z
Denominador racional
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3 2 -5 + z - 3*z + 7*z
$$z^{3} - 3 z^{2} + 7 z - 5$$
-5 + z^3 - 3*z^2 + 7*z
Unión de expresiones racionales
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-5 + z*(7 + z*(-3 + z))
$$z \left(z \left(z - 3\right) + 7\right) - 5$$
-5 + z*(7 + z*(-3 + z))