Sr Examen
Factorizar el polinomio -2-3*x+2*x+5*x^3+4
Solución
Ha introducido
[src]
3 -2 - 3*x + 2*x + 5*x + 4
$$\left(5 x^{3} + \left(2 x + \left(- 3 x - 2\right)\right)\right) + 4$$
-2 - 3*x + 2*x + 5*x^3 + 4
Factorización
[src]
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$$\left(x + \left(\frac{\left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) \sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}}{3} + \frac{1}{5 \left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) \sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}}\right)\right) \left(x + \left(\frac{1}{5 \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right) \sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}} + \frac{\left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right) \sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}}{3}\right)\right) \left(x + \left(\frac{1}{5 \sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}} + \frac{\sqrt[3]{\frac{3 \sqrt{2010}}{25} + \frac{27}{5}}}{3}\right)\right)$$
((x + (27/5 + 3*sqrt(2010)/25)^(1/3)*(-1/2 - i*sqrt(3)/2)/3 + 1/(5*(-1/2 - i*sqrt(3)/2)*(27/5 + 3*sqrt(2010)/25)^(1/3)))*(x + (27/5 + 3*sqrt(2010)/25)^(1/3)*(-1/2 + i*sqrt(3)/2)/3 + 1/(5*(-1/2 + i*sqrt(3)/2)*(27/5 + 3*sqrt(2010)/25)^(1/3))))*(x + (27/5 + 3*sqrt(2010)/25)^(1/3)/3 + 1/(5*(27/5 + 3*sqrt(2010)/25)^(1/3)))