Sr Examen

Ecuación diferencial (y+2)dx-(2x+y-4)dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
      d          d                   d                  
2 + 4*--(y(x)) - --(y(x))*y(x) - 2*x*--(y(x)) + y(x) = 0
      dx         dx                  dx                 
$$- 2 x \frac{d}{d x} y{\left(x \right)} - y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} + 4 \frac{d}{d x} y{\left(x \right)} + 2 = 0$$
-2*x*y' - y*y' + y + 4*y' + 2 = 0
Respuesta [src]
                   _____________________
            C1   \/ C1*(-12 + C1 + 4*x) 
y(x) = -2 + -- - -----------------------
            2               2           
$$y{\left(x \right)} = \frac{C_{1}}{2} - \frac{\sqrt{C_{1} \left(C_{1} + 4 x - 12\right)}}{2} - 2$$
                   _____________________
            C1   \/ C1*(-12 + C1 + 4*x) 
y(x) = -2 + -- + -----------------------
            2               2           
$$y{\left(x \right)} = \frac{C_{1}}{2} + \frac{\sqrt{C_{1} \left(C_{1} + 4 x - 12\right)}}{2} - 2$$
Clasificación
factorable
1st exact
linear coefficients
1st power series
lie group
1st exact Integral
linear coefficients Integral