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Ecuación diferencial y'''-2*y''+2*y'=e^x

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
      2                        3           
     d            d           d           x
- 2*---(y(x)) + 2*--(y(x)) + ---(y(x)) = e 
      2           dx           3           
    dx                       dx            
$$2 \frac{d}{d x} y{\left(x \right)} - 2 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = e^{x}$$
2*y' - 2*y'' + y''' = exp(x)
Respuesta [src]
                                         x
y(x) = C1 + (1 + C2*sin(x) + C3*cos(x))*e 
$$y{\left(x \right)} = C_{1} + \left(C_{2} \sin{\left(x \right)} + C_{3} \cos{\left(x \right)} + 1\right) e^{x}$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth order reducible
nth linear constant coeff variation of parameters Integral