Sr Examen

Ecuación diferencial xydx=(x+1)(y-2)dy

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
             d          d                   d            d            
x*y(x) = - 2*--(y(x)) + --(y(x))*y(x) - 2*x*--(y(x)) + x*--(y(x))*y(x)
             dx         dx                  dx           dx           
$$x y{\left(x \right)} = x y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} - 2 x \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} - 2 \frac{d}{d x} y{\left(x \right)}$$
x*y = x*y*y' - 2*x*y' + y*y' - 2*y'
Respuesta [src]
           /    ________________ \
           |   /             -x  |
           |-\/  C1*(1 + x)*e    |
y(x) = -2*W|---------------------|
           \          2          /
$$y{\left(x \right)} = - 2 W\left(- \frac{\sqrt{C_{1} \left(x + 1\right) e^{- x}}}{2}\right)$$
           /   ________________\
           |  /             -x |
           |\/  C1*(1 + x)*e   |
y(x) = -2*W|-------------------|
           \         2         /
$$y{\left(x \right)} = - 2 W\left(\frac{\sqrt{C_{1} \left(x + 1\right) e^{- x}}}{2}\right)$$
Clasificación
factorable
separable
1st power series
lie group
separable Integral