Sr Examen

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log^2(7,x+5)>=log(7,x-2)*logx-2(x+5) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
   2                log(7)                     
log (7, x + 5) >= ----------*log(x) - 2*(x + 5)
                  log(x - 2)                   
$$\log{\left(7 \right)}^{2} \geq \frac{\log{\left(7 \right)}}{\log{\left(x - 2 \right)}} \log{\left(x \right)} - 2 \left(x + 5\right)$$
log(7, x + 5)^2 >= (log(7)/log(x - 2))*log(x) - 2*(x + 5)