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log(x,x+1)+log(x+1,x+2)+log(x+2,x)≥log(x,x+2)+log(x+2,x+1) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
  log(x)     log(x + 1)   log(x + 2)      log(x)     log(x + 2)
---------- + ---------- + ---------- >= ---------- + ----------
log(x + 1)   log(x + 2)     log(x)      log(x + 2)   log(x + 1)
$$\left(\frac{\log{\left(x \right)}}{\log{\left(x + 1 \right)}} + \frac{\log{\left(x + 1 \right)}}{\log{\left(x + 2 \right)}}\right) + \frac{\log{\left(x + 2 \right)}}{\log{\left(x \right)}} \geq \frac{\log{\left(x \right)}}{\log{\left(x + 2 \right)}} + \frac{\log{\left(x + 2 \right)}}{\log{\left(x + 1 \right)}}$$
log(x)/log(x + 1) + log(x + 1)/log(x + 2) + log(x + 2)/log(x) >= log(x)/log(x + 2) + log(x + 2)/log(x + 1)
Solución de la desigualdad en el gráfico