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Resolver desigualdades/ log(16-4x)/log(1/3)<=log(x^2-9x+20)/log(1/3)+log(x+5)/log(3)

log(16-4x)/log(1/3)<=log(x^2-9x+20)/log(1/3)+log(x+5)/log(3) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src] 
                    / 2           \             
log(16 - 4*x)    log\x  - 9*x + 20/   log(x + 5)
------------- <= ------------------ + ----------
   log(1/3)           log(1/3)          log(3)
log⁡(16−4x)log⁡(13)≤log⁡(x+5)log⁡(3)+log⁡((x2−9x)+20)log⁡(13)\frac{\log{\left(16 - 4 x \right)}}{\log{\left(\frac{1}{3} \right)}} \leq \frac{\log{\left(x + 5 \right)}}{\log{\left(3 \right)}} + \frac{\log{\left(\left(x^{2} - 9 x\right) + 20 \right)}}{\log{\left(\frac{1}{3} \right)}} 
log(16 - 4*x)/log(1/3) <= log(x + 5)/log(3) + log(x^2 - 9*x + 20)/log(1/3)
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