Integral de sqrt(((a1+b1)^2)*t+((a2+b2)^2)*t+((a3+b3)^2)*t) dt
Solución
Respuesta (Indefinida)
[src]
// 3/2 \
|| / 2 2 2 \ |
/ || 2*\(a1 + b1) *t + (a2 + b2) *t + (a3 + b3) *t/ 2 2 2 2 2 2 |
| ||------------------------------------------------------------------- for a1 + a2 + a3 + b1 + b2 + b3 + 2*a1*b1 + 2*a2*b2 + 2*a3*b3 != 0|
| ____________________________________________ || / 2 2 2 2 2 2 \ |
| / 2 2 2 ||3*\a1 + a2 + a3 + b1 + b2 + b3 + 2*a1*b1 + 2*a2*b2 + 2*a3*b3/ |
| \/ (a1 + b1) *t + (a2 + b2) *t + (a3 + b3) *t dt = C + |< |
| || 3/2 |
/ || / 2 2 2 \ |
|| 2*\(a1 + b1) *t + (a2 + b2) *t + (a3 + b3) *t/ |
|| ------------------------------------------------- otherwise |
|| / 2 2 2\ |
\\ 3*\(a1 + b1) + (a2 + b2) + (a3 + b3) / /
∫ t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) d t = C + { 2 ( t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) ) 3 2 3 ( a 1 2 + 2 a 1 b 1 + a 2 2 + 2 a 2 b 2 + a 3 2 + 2 a 3 b 3 + b 1 2 + b 2 2 + b 3 2 ) for a 1 2 + 2 a 1 b 1 + a 2 2 + 2 a 2 b 2 + a 3 2 + 2 a 3 b 3 + b 1 2 + b 2 2 + b 3 2 ≠ 0 2 ( t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) ) 3 2 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) otherwise \int \sqrt{t \left(a_{3} + b_{3}\right)^{2} + \left(t \left(a_{1} + b_{1}\right)^{2} + t \left(a_{2} + b_{2}\right)^{2}\right)}\, dt = C + \begin{cases} \frac{2 \left(t \left(a_{3} + b_{3}\right)^{2} + \left(t \left(a_{1} + b_{1}\right)^{2} + t \left(a_{2} + b_{2}\right)^{2}\right)\right)^{\frac{3}{2}}}{3 \left(a_{1}^{2} + 2 a_{1} b_{1} + a_{2}^{2} + 2 a_{2} b_{2} + a_{3}^{2} + 2 a_{3} b_{3} + b_{1}^{2} + b_{2}^{2} + b_{3}^{2}\right)} & \text{for}\: a_{1}^{2} + 2 a_{1} b_{1} + a_{2}^{2} + 2 a_{2} b_{2} + a_{3}^{2} + 2 a_{3} b_{3} + b_{1}^{2} + b_{2}^{2} + b_{3}^{2} \neq 0 \\\frac{2 \left(t \left(a_{3} + b_{3}\right)^{2} + \left(t \left(a_{1} + b_{1}\right)^{2} + t \left(a_{2} + b_{2}\right)^{2}\right)\right)^{\frac{3}{2}}}{3 \left(\left(a_{1} + b_{1}\right)^{2} + \left(a_{2} + b_{2}\right)^{2} + \left(a_{3} + b_{3}\right)^{2}\right)} & \text{otherwise} \end{cases} ∫ t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) d t = C + ⎩ ⎨ ⎧ 3 ( a 1 2 + 2 a 1 b 1 + a 2 2 + 2 a 2 b 2 + a 3 2 + 2 a 3 b 3 + b 1 2 + b 2 2 + b 3 2 ) 2 ( t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) ) 2 3 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) 2 ( t ( a 3 + b 3 ) 2 + ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 ) ) 2 3 for a 1 2 + 2 a 1 b 1 + a 2 2 + 2 a 2 b 2 + a 3 2 + 2 a 3 b 3 + b 1 2 + b 2 2 + b 3 2 = 0 otherwise
3/2
/ 2 2 2\
2*\t*(a1 + b1) + t*(a2 + b2) + t*(a3 + b3) /
-------------------------------------------------
/ 2 2 2\
3*\(a1 + b1) + (a2 + b2) + (a3 + b3) /
2 ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 + t ( a 3 + b 3 ) 2 ) 3 2 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) \frac{2 \left(t \left(a_{1} + b_{1}\right)^{2} + t \left(a_{2} + b_{2}\right)^{2} + t \left(a_{3} + b_{3}\right)^{2}\right)^{\frac{3}{2}}}{3 \left(\left(a_{1} + b_{1}\right)^{2} + \left(a_{2} + b_{2}\right)^{2} + \left(a_{3} + b_{3}\right)^{2}\right)} 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) 2 ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 + t ( a 3 + b 3 ) 2 ) 2 3
=
3/2
/ 2 2 2\
2*\t*(a1 + b1) + t*(a2 + b2) + t*(a3 + b3) /
-------------------------------------------------
/ 2 2 2\
3*\(a1 + b1) + (a2 + b2) + (a3 + b3) /
2 ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 + t ( a 3 + b 3 ) 2 ) 3 2 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) \frac{2 \left(t \left(a_{1} + b_{1}\right)^{2} + t \left(a_{2} + b_{2}\right)^{2} + t \left(a_{3} + b_{3}\right)^{2}\right)^{\frac{3}{2}}}{3 \left(\left(a_{1} + b_{1}\right)^{2} + \left(a_{2} + b_{2}\right)^{2} + \left(a_{3} + b_{3}\right)^{2}\right)} 3 ( ( a 1 + b 1 ) 2 + ( a 2 + b 2 ) 2 + ( a 3 + b 3 ) 2 ) 2 ( t ( a 1 + b 1 ) 2 + t ( a 2 + b 2 ) 2 + t ( a 3 + b 3 ) 2 ) 2 3
2*(t*(a1 + b1)^2 + t*(a2 + b2)^2 + t*(a3 + b3)^2)^(3/2)/(3*((a1 + b1)^2 + (a2 + b2)^2 + (a3 + b3)^2))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.