Integral de sin^2(2x+5) dx
Solución
Respuesta (Indefinida)
[src]
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| 3 4 2
| 2 x tan (5/2 + x) tan(5/2 + x) x*tan (5/2 + x) 2*x*tan (5/2 + x)
| sin (2*x + 5) dx = C + ------------------------------------- + ------------------------------------- - ------------------------------------- + ------------------------------------- + -------------------------------------
| 4 2 4 2 4 2 4 2 4 2
/ 2 + 2*tan (5/2 + x) + 4*tan (5/2 + x) 2 + 2*tan (5/2 + x) + 4*tan (5/2 + x) 2 + 2*tan (5/2 + x) + 4*tan (5/2 + x) 2 + 2*tan (5/2 + x) + 4*tan (5/2 + x) 2 + 2*tan (5/2 + x) + 4*tan (5/2 + x)
∫sin2(2x+5)dx=C+2tan4(x+25)+4tan2(x+25)+2xtan4(x+25)+2tan4(x+25)+4tan2(x+25)+22xtan2(x+25)+2tan4(x+25)+4tan2(x+25)+2x+2tan4(x+25)+4tan2(x+25)+2tan3(x+25)−2tan4(x+25)+4tan2(x+25)+2tan(x+25)
Gráfica
2 2
cos (7) sin (7) cos(7)*sin(7) cos(5)*sin(5)
------- + ------- - ------------- + -------------
2 2 4 4
−4sin(7)cos(7)+4sin(5)cos(5)+2sin2(7)+2cos2(7)
=
2 2
cos (7) sin (7) cos(7)*sin(7) cos(5)*sin(5)
------- + ------- - ------------- + -------------
2 2 4 4
−4sin(7)cos(7)+4sin(5)cos(5)+2sin2(7)+2cos2(7)
cos(7)^2/2 + sin(7)^2/2 - cos(7)*sin(7)/4 + cos(5)*sin(5)/4
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.