Integral de sec^5(x) dx
Solución
Respuesta (Indefinida)
[src]
/
| 3
| 5 3*log(-1 + sin(x)) 3*log(1 + sin(x)) -5*sin(x) + 3*sin (x)
| sec (x) dx = C - ------------------ + ----------------- - --------------------------
| 16 16 2 4
/ 8 - 16*sin (x) + 8*sin (x)
$$\int \sec^{5}{\left(x \right)}\, dx = C - \frac{3 \sin^{3}{\left(x \right)} - 5 \sin{\left(x \right)}}{8 \sin^{4}{\left(x \right)} - 16 \sin^{2}{\left(x \right)} + 8} - \frac{3 \log{\left(\sin{\left(x \right)} - 1 \right)}}{16} + \frac{3 \log{\left(\sin{\left(x \right)} + 1 \right)}}{16}$$
3
3*log(1 - sin(1)) 3*log(1 + sin(1)) -5*sin(1) + 3*sin (1)
- ----------------- + ----------------- - --------------------------
16 16 2 4
8 - 16*sin (1) + 8*sin (1)
$$\frac{3 \log{\left(\sin{\left(1 \right)} + 1 \right)}}{16} - \frac{3 \log{\left(1 - \sin{\left(1 \right)} \right)}}{16} - \frac{- 5 \sin{\left(1 \right)} + 3 \sin^{3}{\left(1 \right)}}{- 16 \sin^{2}{\left(1 \right)} + 8 \sin^{4}{\left(1 \right)} + 8}$$
=
3
3*log(1 - sin(1)) 3*log(1 + sin(1)) -5*sin(1) + 3*sin (1)
- ----------------- + ----------------- - --------------------------
16 16 2 4
8 - 16*sin (1) + 8*sin (1)
$$\frac{3 \log{\left(\sin{\left(1 \right)} + 1 \right)}}{16} - \frac{3 \log{\left(1 - \sin{\left(1 \right)} \right)}}{16} - \frac{- 5 \sin{\left(1 \right)} + 3 \sin^{3}{\left(1 \right)}}{- 16 \sin^{2}{\left(1 \right)} + 8 \sin^{4}{\left(1 \right)} + 8}$$
-3*log(1 - sin(1))/16 + 3*log(1 + sin(1))/16 - (-5*sin(1) + 3*sin(1)^3)/(8 - 16*sin(1)^2 + 8*sin(1)^4)
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.