Integral de 1/(256-x^4)^(1/2) dx
Solución
Respuesta (Indefinida)
[src]
_ / | 4 2*pi*I\
/ |_ |1/4, 1/2 | x *e |
| x*Gamma(1/4)* | | | ----------|
| 1 2 1 \ 5/4 | 256 /
| ------------- dx = C + -----------------------------------------
| __________ 64*Gamma(5/4)
| / 4
| \/ 256 - x
|
/
$$\int \frac{1}{\sqrt{256 - x^{4}}}\, dx = C + \frac{x \Gamma\left(\frac{1}{4}\right) {{}_{2}F_{1}\left(\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle| {\frac{x^{4} e^{2 i \pi}}{256}} \right)}}{64 \Gamma\left(\frac{5}{4}\right)}$$
_ _
|_ /1/4, 1/2 | \ |_ /1/4, 1/2 | \
Gamma(1/4)* | | | 1/16| Gamma(1/4)* | | | 1|
2 1 \ 5/4 | / 2 1 \ 5/4 | /
- --------------------------------- + ------------------------------
32*Gamma(5/4) 16*Gamma(5/4)
$$- \frac{\Gamma\left(\frac{1}{4}\right) {{}_{2}F_{1}\left(\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle| {\frac{1}{16}} \right)}}{32 \Gamma\left(\frac{5}{4}\right)} + \frac{\Gamma\left(\frac{1}{4}\right) {{}_{2}F_{1}\left(\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle| {1} \right)}}{16 \Gamma\left(\frac{5}{4}\right)}$$
=
_ _
|_ /1/4, 1/2 | \ |_ /1/4, 1/2 | \
Gamma(1/4)* | | | 1/16| Gamma(1/4)* | | | 1|
2 1 \ 5/4 | / 2 1 \ 5/4 | /
- --------------------------------- + ------------------------------
32*Gamma(5/4) 16*Gamma(5/4)
$$- \frac{\Gamma\left(\frac{1}{4}\right) {{}_{2}F_{1}\left(\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle| {\frac{1}{16}} \right)}}{32 \Gamma\left(\frac{5}{4}\right)} + \frac{\Gamma\left(\frac{1}{4}\right) {{}_{2}F_{1}\left(\begin{matrix} \frac{1}{4}, \frac{1}{2} \\ \frac{5}{4} \end{matrix}\middle| {1} \right)}}{16 \Gamma\left(\frac{5}{4}\right)}$$
-gamma(1/4)*hyper((1/4, 1/2), (5/4,), 1/16)/(32*gamma(5/4)) + gamma(1/4)*hyper((1/4, 1/2), (5/4,), 1)/(16*gamma(5/4))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.