Integral de x^(1÷3)/(1+sqrt(x)) dx
Solución
Respuesta (Indefinida)
[src]
/ -2*pi*I / pi*I\ 2*pi*I / 5*pi*I\
| ------- | ----| ------ | ------|
| 3 ___ 3 ___ / 6 ___ pi*I\ 5/6 3 | 6 ___ 3 | 3 | 6 ___ 3 |
| \/ x 8*\/ x *Gamma(8/3) 16*Gamma(8/3)*log\1 - \/ x *e / 16*x *Gamma(8/3) 16*e *Gamma(8/3)*log\1 - \/ x *e / 16*e *Gamma(8/3)*log\1 - \/ x *e /
| --------- dx = C - ------------------ - ---------------------------------- + ------------------ - ------------------------------------------- - --------------------------------------------
| ___ Gamma(11/3) 3*Gamma(11/3) 5*Gamma(11/3) 3*Gamma(11/3) 3*Gamma(11/3)
| 1 + \/ x
|
/
∫x+13xdx=C+5Γ(311)16x65Γ(38)−Γ(311)83xΓ(38)−3Γ(311)16e−32iπlog(−6xe3iπ+1)Γ(38)−3Γ(311)16log(−6xeiπ+1)Γ(38)−3Γ(311)16e32iπlog(−6xe35iπ+1)Γ(38)
-2*pi*I / pi*I\ 2*pi*I / 5*pi*I\
------- | ----| ------ | ------|
/ pi*I\ 3 | 3 | 3 | 3 |
24*Gamma(8/3) 16*Gamma(8/3)*log\1 - e / 16*e *Gamma(8/3)*log\1 - e / 16*e *Gamma(8/3)*log\1 - e /
- ------------- - ---------------------------- - ------------------------------------- - --------------------------------------
5*Gamma(11/3) 3*Gamma(11/3) 3*Gamma(11/3) 3*Gamma(11/3)
−3Γ(311)16e32iπlog(1−e35iπ)Γ(38)−5Γ(311)24Γ(38)−3Γ(311)16log(1−eiπ)Γ(38)−3Γ(311)16e−32iπlog(1−e3iπ)Γ(38)
=
-2*pi*I / pi*I\ 2*pi*I / 5*pi*I\
------- | ----| ------ | ------|
/ pi*I\ 3 | 3 | 3 | 3 |
24*Gamma(8/3) 16*Gamma(8/3)*log\1 - e / 16*e *Gamma(8/3)*log\1 - e / 16*e *Gamma(8/3)*log\1 - e /
- ------------- - ---------------------------- - ------------------------------------- - --------------------------------------
5*Gamma(11/3) 3*Gamma(11/3) 3*Gamma(11/3) 3*Gamma(11/3)
−3Γ(311)16e32iπlog(1−e35iπ)Γ(38)−5Γ(311)24Γ(38)−3Γ(311)16log(1−eiπ)Γ(38)−3Γ(311)16e−32iπlog(1−e3iπ)Γ(38)
-24*gamma(8/3)/(5*gamma(11/3)) - 16*gamma(8/3)*log(1 - exp_polar(pi*i))/(3*gamma(11/3)) - 16*exp(-2*pi*i/3)*gamma(8/3)*log(1 - exp_polar(pi*i/3))/(3*gamma(11/3)) - 16*exp(2*pi*i/3)*gamma(8/3)*log(1 - exp_polar(5*pi*i/3))/(3*gamma(11/3))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.