Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{4 x + \left(5 - x^{2}\right)}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{4 x + \left(5 - x^{2}\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{\left(x + 1\right) \left(3 x + 2\right)}{\left(-1\right) \left(x - 5\right) \left(x + 1\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(- \frac{3 x + 2}{x - 5}\right) = $$
$$- \frac{2 + 3}{-5 + 1} = $$
= 5/4
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{4 x + \left(5 - x^{2}\right)}\right) = \frac{5}{4}$$