Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{x}{3 x^{4} + \left(2 x^{2} + \left(1 - x\right)\right)}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{x}{3 x^{4} + \left(2 x^{2} + \left(1 - x\right)\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{x}{3 x^{4} + 2 x^{2} - x + 1}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{x}{3 x^{4} + 2 x^{2} - x + 1}\right) = $$
$$\frac{2}{- 2 + 1 + 2 \cdot 2^{2} + 3 \cdot 2^{4}} = $$
= 2/55
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{x}{3 x^{4} + \left(2 x^{2} + \left(1 - x\right)\right)}\right) = \frac{2}{55}$$