Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{- 2 x + \left(x^{2} + 1\right)}{- 14 x + \left(x^{3} + 2\right)}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{- 2 x + \left(x^{2} + 1\right)}{- 14 x + \left(x^{3} + 2\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{\left(x - 1\right)^{2}}{x^{3} - 14 x + 2}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{\left(x - 1\right)^{2}}{x^{3} - 14 x + 2}\right) = $$
$$\frac{\left(-1 + 1\right)^{2}}{-14 + 1^{3} + 2} = $$
= 0
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{- 2 x + \left(x^{2} + 1\right)}{- 14 x + \left(x^{3} + 2\right)}\right) = 0$$