Tenemos la indeterminación de tipo
oo/oo,
tal que el límite para el numerador es
$$\lim_{x \to \infty}\left(\log{\left(x \right)}^{3} + 3 \log{\left(2 \right)} \log{\left(x \right)}^{2} + 3 \log{\left(2 \right)}^{2} \log{\left(x \right)} + \log{\left(2 \right)}^{3}\right) = \infty$$
y el límite para el denominador es
$$\lim_{x \to \infty}\left(6 x^{\frac{7}{3}}\right) = \infty$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to \infty}\left(\frac{\log{\left(2 x \right)}^{3}}{6 x^{\frac{7}{3}}}\right)$$
=
Introducimos una pequeña modificación de la función bajo el signo del límite
$$\lim_{x \to \infty}\left(\frac{\log{\left(2 x \right)}^{3}}{6 x^{\frac{7}{3}}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(\log{\left(x \right)}^{3} + 3 \log{\left(2 \right)} \log{\left(x \right)}^{2} + 3 \log{\left(2 \right)}^{2} \log{\left(x \right)} + \log{\left(2 \right)}^{3}\right)}{\frac{d}{d x} 6 x^{\frac{7}{3}}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{3 \log{\left(x \right)}^{2}}{x} + \frac{6 \log{\left(2 \right)} \log{\left(x \right)}}{x} + \frac{3 \log{\left(2 \right)}^{2}}{x}}{14 x^{\frac{4}{3}}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(\frac{3 \log{\left(x \right)}^{2}}{x} + \frac{6 \log{\left(2 \right)} \log{\left(x \right)}}{x} + \frac{3 \log{\left(2 \right)}^{2}}{x}\right)}{\frac{d}{d x} 14 x^{\frac{4}{3}}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{3 \left(- \frac{3 \log{\left(x \right)}^{2}}{x^{2}} - \frac{6 \log{\left(2 \right)} \log{\left(x \right)}}{x^{2}} + \frac{6 \log{\left(x \right)}}{x^{2}} - \frac{3 \log{\left(2 \right)}^{2}}{x^{2}} + \frac{6 \log{\left(2 \right)}}{x^{2}}\right)}{56 \sqrt[3]{x}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(- \frac{3 \log{\left(x \right)}^{2}}{x^{2}} - \frac{6 \log{\left(2 \right)} \log{\left(x \right)}}{x^{2}} + \frac{6 \log{\left(x \right)}}{x^{2}} - \frac{3 \log{\left(2 \right)}^{2}}{x^{2}} + \frac{6 \log{\left(2 \right)}}{x^{2}}\right)}{\frac{d}{d x} \frac{56 \sqrt[3]{x}}{3}}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{9 x^{\frac{2}{3}} \left(\frac{6 \log{\left(x \right)}^{2}}{x^{3}} - \frac{18 \log{\left(x \right)}}{x^{3}} + \frac{12 \log{\left(2 \right)} \log{\left(x \right)}}{x^{3}} - \frac{18 \log{\left(2 \right)}}{x^{3}} + \frac{6 \log{\left(2 \right)}^{2}}{x^{3}} + \frac{6}{x^{3}}\right)}{56}\right)$$
=
$$\lim_{x \to \infty}\left(\frac{9 x^{\frac{2}{3}} \left(\frac{6 \log{\left(x \right)}^{2}}{x^{3}} - \frac{18 \log{\left(x \right)}}{x^{3}} + \frac{12 \log{\left(2 \right)} \log{\left(x \right)}}{x^{3}} - \frac{18 \log{\left(2 \right)}}{x^{3}} + \frac{6 \log{\left(2 \right)}^{2}}{x^{3}} + \frac{6}{x^{3}}\right)}{56}\right)$$
=
$$0$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 3 vez (veces)