Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{\left(x + y\right) \cos{\left(1 \right)} \sin{\left(1 \right)}}{x y}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{\left(x + y\right) \cos{\left(1 \right)} \sin{\left(1 \right)}}{x y}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x + y\right) \sin{\left(1 \right)} \cos{\left(1 \right)}}{x y}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x + y\right) \sin{\left(2 \right)}}{2 x y}\right) = $$
$$\frac{y \sin{\left(2 \right)}}{0 \cdot 2 y} = $$
= oo
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{\left(x + y\right) \cos{\left(1 \right)} \sin{\left(1 \right)}}{x y}\right) = \infty$$