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Lógica matemática/ (xv(-y)->((z->y)v(-y)vx))&((x)v(-(x->(x->x))))->y

Expresión (xv(-y)->((z->y)v(-y)vx))&((x)v(-(x->(x->x))))->y

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    ((x∨(¬(x⇒(x⇒x))))∧((x∨(¬y))⇒(x∨(¬y)∨(z⇒y))))⇒y
    (((x∨¬y)⇒(x∨(z⇒y)∨¬y))∧(x∨x⇏(x⇒x)))⇒y\left(\left(\left(x \vee \neg y\right) \Rightarrow \left(x \vee \left(z \Rightarrow y\right) \vee \neg y\right)\right) \wedge \left(x \vee x \not\Rightarrow \left(x \Rightarrow x\right)\right)\right) \Rightarrow y
    Solución detallada
    x⇒x=1x \Rightarrow x = 1
    x⇒(x⇒x)=1x \Rightarrow \left(x \Rightarrow x\right) = 1
    x⇏(x⇒x)=Falsex \not\Rightarrow \left(x \Rightarrow x\right) = \text{False}
    x∨x⇏(x⇒x)=xx \vee x \not\Rightarrow \left(x \Rightarrow x\right) = x
    z⇒y=y∨¬zz \Rightarrow y = y \vee \neg z
    x∨(z⇒y)∨¬y=1x \vee \left(z \Rightarrow y\right) \vee \neg y = 1
    (x∨¬y)⇒(x∨(z⇒y)∨¬y)=1\left(x \vee \neg y\right) \Rightarrow \left(x \vee \left(z \Rightarrow y\right) \vee \neg y\right) = 1
    ((x∨¬y)⇒(x∨(z⇒y)∨¬y))∧(x∨x⇏(x⇒x))=x\left(\left(x \vee \neg y\right) \Rightarrow \left(x \vee \left(z \Rightarrow y\right) \vee \neg y\right)\right) \wedge \left(x \vee x \not\Rightarrow \left(x \Rightarrow x\right)\right) = x
    (((x∨¬y)⇒(x∨(z⇒y)∨¬y))∧(x∨x⇏(x⇒x)))⇒y=y∨¬x\left(\left(\left(x \vee \neg y\right) \Rightarrow \left(x \vee \left(z \Rightarrow y\right) \vee \neg y\right)\right) \wedge \left(x \vee x \not\Rightarrow \left(x \Rightarrow x\right)\right)\right) \Rightarrow y = y \vee \neg x
    Simplificación [src]
    y∨¬xy \vee \neg x 
    y∨(¬x)
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    y∨¬xy \vee \neg x 
    y∨(¬x)
    FNC [src]
    Ya está reducido a FNC
    y∨¬xy \vee \neg x 
    y∨(¬x)
    FNDP [src]
    y∨¬xy \vee \neg x 
    y∨(¬x)
    FNCD [src]
    y∨¬xy \vee \neg x 
    y∨(¬x)
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