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Ecuación diferencial (x+siny)dx+(xcosy+siny)dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
    d                      d                                 
x + --(y(x))*sin(y(x)) + x*--(y(x))*cos(y(x)) + sin(y(x)) = 0
    dx                     dx                                
$$x \cos{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + x + \sin{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + \sin{\left(y{\left(x \right)} \right)} = 0$$
x*cos(y)*y' + x + sin(y)*y' + sin(y) = 0
Respuesta [src]
              /     _________________________________      \
              |    /      4       2      2         2       |
              |- \/  4 - x  - 4*C1  + 4*x  + 4*C1*x   + 2*x|
y(x) = -2*atan|--------------------------------------------|
              |                    2                       |
              \               2 + x  - 2*C1                /
$$y{\left(x \right)} = - 2 \operatorname{atan}{\left(\frac{2 x - \sqrt{- 4 C_{1}^{2} + 4 C_{1} x^{2} - x^{4} + 4 x^{2} + 4}}{- 2 C_{1} + x^{2} + 2} \right)}$$
              /   _________________________________      \
              |  /      4       2      2         2       |
              |\/  4 - x  - 4*C1  + 4*x  + 4*C1*x   + 2*x|
y(x) = -2*atan|------------------------------------------|
              |                   2                      |
              \              2 + x  - 2*C1               /
$$y{\left(x \right)} = - 2 \operatorname{atan}{\left(\frac{2 x + \sqrt{- 4 C_{1}^{2} + 4 C_{1} x^{2} - x^{4} + 4 x^{2} + 4}}{- 2 C_{1} + x^{2} + 2} \right)}$$
Clasificación
1st exact
1st power series
lie group
1st exact Integral