Integral de cos^3(2x-1) dx
Solución
Respuesta (Indefinida)
[src]
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| 3 5
| 3 2*tan (-1/2 + x) 3*tan (-1/2 + x) 3*tan(-1/2 + x)
| cos (2*x - 1) dx = C + ---------------------------------------------------------- + ---------------------------------------------------------- + ----------------------------------------------------------
| 6 2 4 6 2 4 6 2 4
/ 3 + 3*tan (-1/2 + x) + 9*tan (-1/2 + x) + 9*tan (-1/2 + x) 3 + 3*tan (-1/2 + x) + 9*tan (-1/2 + x) + 9*tan (-1/2 + x) 3 + 3*tan (-1/2 + x) + 9*tan (-1/2 + x) + 9*tan (-1/2 + x)
$$\int \cos^{3}{\left(2 x - 1 \right)}\, dx = C + \frac{3 \tan^{5}{\left(x - \frac{1}{2} \right)}}{3 \tan^{6}{\left(x - \frac{1}{2} \right)} + 9 \tan^{4}{\left(x - \frac{1}{2} \right)} + 9 \tan^{2}{\left(x - \frac{1}{2} \right)} + 3} + \frac{2 \tan^{3}{\left(x - \frac{1}{2} \right)}}{3 \tan^{6}{\left(x - \frac{1}{2} \right)} + 9 \tan^{4}{\left(x - \frac{1}{2} \right)} + 9 \tan^{2}{\left(x - \frac{1}{2} \right)} + 3} + \frac{3 \tan{\left(x - \frac{1}{2} \right)}}{3 \tan^{6}{\left(x - \frac{1}{2} \right)} + 9 \tan^{4}{\left(x - \frac{1}{2} \right)} + 9 \tan^{2}{\left(x - \frac{1}{2} \right)} + 3}$$
3
2*sin (1) 2
--------- + cos (1)*sin(1)
3
$$\sin{\left(1 \right)} \cos^{2}{\left(1 \right)} + \frac{2 \sin^{3}{\left(1 \right)}}{3}$$
=
3
2*sin (1) 2
--------- + cos (1)*sin(1)
3
$$\sin{\left(1 \right)} \cos^{2}{\left(1 \right)} + \frac{2 \sin^{3}{\left(1 \right)}}{3}$$
2*sin(1)^3/3 + cos(1)^2*sin(1)
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.