Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{2 x + \left(x^{3} - x^{2}\right)}{x^{2} + x}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{2 x + \left(x^{3} - x^{2}\right)}{x^{2} + x}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{x \left(x^{2} - x + 2\right)}{x \left(x + 1\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{x^{2} - x + 2}{x + 1}\right) = $$
$$\frac{- 2 + 2 + 2^{2}}{1 + 2} = $$
= 4/3
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{2 x + \left(x^{3} - x^{2}\right)}{x^{2} + x}\right) = \frac{4}{3}$$