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Expresión (a∨b)∨(a∧c)=a∨b∧a∨c=a∧b∧(a∨c)=ab∧(a∨c)(ab∨abc∨bc∨c)(c∨ac∨abc)=(ab∨c)(ac∨c)=abac∨cac∨abc∨cc

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b∧(a∨c))⇔(a∨b∨(a∧c))⇔(a∨c∨(a∧b))⇔(c∨(a∧c)∨(a∧b∧c))⇔((c∨(a∧b))∧(c∨(a∧c)))⇔(a∧b∧(a∨c)∧(c∨(a∧c)∨(a∧b∧c))∧(c∨(a∧b)∨(b∧c)∨(a∧b∧c)))
    $$\left(\left(c \vee \left(a \wedge b\right)\right) \wedge \left(c \vee \left(a \wedge c\right)\right)\right) ⇔ \left(a \wedge b \wedge \left(a \vee c\right)\right) ⇔ \left(a \wedge b \wedge \left(a \vee c\right) \wedge \left(c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right) \wedge \left(c \vee \left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right)\right) ⇔ \left(a \vee b \vee \left(a \wedge c\right)\right) ⇔ \left(a \vee c \vee \left(a \wedge b\right)\right) ⇔ \left(c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right)$$
    Solución detallada
    $$a \wedge b \wedge \left(a \vee c\right) = a \wedge b$$
    $$a \vee b \vee \left(a \wedge c\right) = a \vee b$$
    $$a \vee c \vee \left(a \wedge b\right) = a \vee c$$
    $$c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) = c$$
    $$c \vee \left(a \wedge c\right) = c$$
    $$\left(c \vee \left(a \wedge b\right)\right) \wedge \left(c \vee \left(a \wedge c\right)\right) = c$$
    $$c \vee \left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(a \wedge b \wedge c\right) = c \vee \left(a \wedge b\right)$$
    $$a \wedge b \wedge \left(a \vee c\right) \wedge \left(c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right) \wedge \left(c \vee \left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right) = a \wedge b \wedge c$$
    $$\left(\left(c \vee \left(a \wedge b\right)\right) \wedge \left(c \vee \left(a \wedge c\right)\right)\right) ⇔ \left(a \wedge b \wedge \left(a \vee c\right)\right) ⇔ \left(a \wedge b \wedge \left(a \vee c\right) \wedge \left(c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right) \wedge \left(c \vee \left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right)\right) ⇔ \left(a \vee b \vee \left(a \wedge c\right)\right) ⇔ \left(a \vee c \vee \left(a \wedge b\right)\right) ⇔ \left(c \vee \left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right)\right) = \left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
    (a∨(¬b))∧(a∨(¬c))∧(b∨(¬a))∧(b∨(¬c))∧(c∨(¬a))∧(c∨(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
    (a∨(¬b))∧(a∨(¬c))∧(b∨(¬a))∧(b∨(¬c))∧(c∨(¬a))∧(c∨(¬b))
    FNDP [src]
    $$\left(a \wedge b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
    (a∧b∧c)∨((¬a)∧(¬b)∧(¬c))
    FND [src]
    $$\left(a \wedge b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \neg a\right) \vee \left(a \wedge b \wedge c \wedge \neg b\right) \vee \left(a \wedge b \wedge c \wedge \neg c\right) \vee \left(a \wedge b \wedge \neg a \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg a \wedge \neg c\right) \vee \left(a \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \neg a \wedge \neg b\right) \vee \left(a \wedge b \wedge c \wedge \neg a \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge c \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \neg a \wedge \neg b \wedge \neg c\right)$$
    (a∧b∧c)∨(a∧b∧c∧(¬a))∨(a∧b∧c∧(¬b))∨(a∧b∧c∧(¬c))∨((¬a)∧(¬b)∧(¬c))∨(a∧b∧(¬a)∧(¬b))∨(a∧c∧(¬a)∧(¬c))∨(b∧c∧(¬b)∧(¬c))∨(a∧(¬a)∧(¬b)∧(¬c))∨(b∧(¬a)∧(¬b)∧(¬c))∨(c∧(¬a)∧(¬b)∧(¬c))∨(a∧b∧c∧(¬a)∧(¬b))∨(a∧b∧c∧(¬a)∧(¬c))∨(a∧b∧c∧(¬b)∧(¬c))∨(a∧b∧(¬a)∧(¬b)∧(¬c))∨(a∧c∧(¬a)∧(¬b)∧(¬c))∨(b∧c∧(¬a)∧(¬b)∧(¬c))∨(a∧b∧c∧(¬a)∧(¬b)∧(¬c))
    FNCD [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
    (a∨(¬b))∧(a∨(¬c))∧(b∨(¬a))∧(b∨(¬c))∧(c∨(¬a))∧(c∨(¬b))