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¿Cómo vas a descomponer esta (e^(3x)+1)/(e^x+1) expresión en fracciones?

Expresión a simplificar:

Solución

Ha introducido [src]
 3*x    
E    + 1
--------
  x     
 E  + 1 
e3x+1ex+1\frac{e^{3 x} + 1}{e^{x} + 1}
(E^(3*x) + 1)/(E^x + 1)
Simplificación general [src]
     x    2*x
1 - e  + e   
e2xex+1e^{2 x} - e^{x} + 1
1 - exp(x) + exp(2*x)
Descomposición de una fracción [src]
1 - exp(x) + exp(2*x)
e2xex+1e^{2 x} - e^{x} + 1
     x    2*x
1 - e  + e   
Respuesta numérica [src]
(1.0 + 2.71828182845905^(3.0*x))/(1.0 + 2.71828182845905^x)
(1.0 + 2.71828182845905^(3.0*x))/(1.0 + 2.71828182845905^x)
Combinatoria [src]
     x    2*x
1 - e  + e   
e2xex+1e^{2 x} - e^{x} + 1
1 - exp(x) + exp(2*x)
Parte trigonométrica [src]
1 + cosh(3*x) + sinh(3*x)
-------------------------
  1 + cosh(x) + sinh(x)  
sinh(3x)+cosh(3x)+1sinh(x)+cosh(x)+1\frac{\sinh{\left(3 x \right)} + \cosh{\left(3 x \right)} + 1}{\sinh{\left(x \right)} + \cosh{\left(x \right)} + 1}
                       3*x
1 + (cosh(1) + sinh(1))   
--------------------------
                        x 
 1 + (cosh(1) + sinh(1))  
(sinh(1)+cosh(1))3x+1(sinh(1)+cosh(1))x+1\frac{\left(\sinh{\left(1 \right)} + \cosh{\left(1 \right)}\right)^{3 x} + 1}{\left(\sinh{\left(1 \right)} + \cosh{\left(1 \right)}\right)^{x} + 1}
                       2*x                      x
1 + (cosh(1) + sinh(1))    - (cosh(1) + sinh(1)) 
(sinh(1)+cosh(1))2x(sinh(1)+cosh(1))x+1\left(\sinh{\left(1 \right)} + \cosh{\left(1 \right)}\right)^{2 x} - \left(\sinh{\left(1 \right)} + \cosh{\left(1 \right)}\right)^{x} + 1
1 + (cosh(1) + sinh(1))^(2*x) - (cosh(1) + sinh(1))^x
Denominador común [src]
     x    2*x
1 - e  + e   
e2xex+1e^{2 x} - e^{x} + 1
1 - exp(x) + exp(2*x)